2020-수학-가형-홀수-15¶
문제¶
풀이¶
from sympy import *
a, x = symbols('a, x')
solve(a**x-sqrt(3),x)
[log(3)/(2*log(a))]
A = Point(log(3)/(2*log(a)), sqrt(3))
B = Point(4,0)
eqn = A.dot(A-B)
eqn
\[\displaystyle \frac{\left(-4 + \frac{\log{\left(3 \right)}}{2 \log{\left(a \right)}}\right) \log{\left(3 \right)}}{2 \log{\left(a \right)}} + 3\]
solve(eqn, log(a))
[log(3)/6, log(3)/2]
exp(sum([log(3)/6, log(3)/2]))
\[\displaystyle 3^{\frac{2}{3}}\]