2019-수학-가형-홀수-6¶
문제¶
풀이¶
from sympy import *
d, f = symbols('d f')
x0= Symbol("x0", positive=True)
p1 = Parabola(Point(f, 0), Line(Point(-d, -1), Point(-d, 1)))
p1 = p1.subs({f:3,d:3})
p1
\[\displaystyle Parabola\left(Point2D\left(3, 0\right), Line2D\left(Point2D\left(-3, -1\right), Point2D\left(-3, 1\right)\right)\right)\]
p1.equation()
\[\displaystyle 12 x - y^{2}\]
F = Point(3,0)
P = Point(x0,sqrt(12*x0))
solve(Eq(P.distance(F),9),x0)
[6]