2019-수학-가형-홀수-3

문제

2019-수학-가형-홀수-3

풀이

%%capture
!pip install --upgrade sympy watermark
from sympy import *

a = symbols('a')
A = Point(2,a,-2)
B = Point(5,-2,1)
C = (1/3)*A+(2/3)*B
solve(C[1],a)
[4.00000000000000]

##실행환경

%load_ext watermark
%watermark --iversions
sympy: 1.7.1